How do i calculate something like this in python? (n*(n-1))/2= 1128 i.E. n is unknown. I can't do it like x = (n*(n-1))/2= 1128

Question

Python, math, no idea to solve

Answer 1

mathematical steps:
(n*(n-1))/2=1128
n*(n-1)=2256
(n-0.5)^2=2256.25
(n-0.5)=47.5
n=48

Answer 2

Use math

Answer 3

Math solution :
n*(n-1)/2 == 1128
<=> n*n/2 - n/2 - 1128 == 0
== a*n*n + b*n + c
Here you can solve it like a quadratic equation
a = 1/2
b = -1/2
c = -1128
delta = b*b - 4*a*c = 1/4 + 4*1128*1/2 > 0
so there are 2 solutions
(-b - sqrt(delta))/ 2*a
(-b + sqrt(delta))/ 2*a

Answer 4

"use math" lol

Answer 5

thanks for your answers. :-)

Answer 6

hi