+ 1
How can I order 2 numbers from the lesser one to the greater one in JavaScript? Please help me to correct my try...
3 Respostas
+ 1
resultado = N1, N2; - this line of code will not work.
var N1 = parseInt(prompt("Escriba un numero"));
var N2 = parseInt(prompt("Escriba otro numero"));
var higher;
var lower;
if (N1 > N2) {
higher = N1;
lower = N2;
} else {
higher = N2;
lower = N1;
}
document.write("El orden ascendente es " + higher + ',' + lower);
It's from higher to lower.If you want from lower to higher just change order inside document.write,like this.
document.write("El orden ascendente es " + lower+ ',' + higher );
If you want to do this thing with more numbers then just 2 ->
you need array.sort method and function which will sort.
+ 3
With Array.sort() you will reorder the array.
Default ordering is done with string values (even if stored values are number), so ordering number is quite failing ^^
However, you can provide a callback function as argument of Array.sort() to perform sort as you want.
The callback function expect two arguments: two items of your array to be compared: return -1 (or any negative value) if first is to be sorted first, 1 (or any positive) if second have to be, 0 if undeterminated... so working callback function to order numbers from lesser to greater will be: function mysort(a,b) { return b-a; }
You can use it for sort() argument as named function, or even as anonymized one: arr.sort(mysort); or even arr.sort(function(a,b) { return b-a; });
Example:
n = true;
arr = [];
while (n) {
n = prompt('Enter a value?');
if (n) arr.push(n);
}
arr.sort(function(a,b) { return a-b; });
alert(''+arr);
0
how would that be for more numbers like you said... with array.sort ?