Challenge!!! Write a digits divider.

Question

Write a program that gets an integer number and separates the digits that compose it.

Examples:
12568 -> 1 2 5 6 8
-829 -> - 8 2 9

Do not use string.

Answer 1

My solution in c++

https://code.sololearn.com/cQD67Otrw0BR/?ref=app

Answer 2

https://code.sololearn.com/c90oIFOzV7LW/#cs

my solution

Answer 3

See my code -

https://code.sololearn.com/cxB3IdJYioig/?ref=app
No string used

Answer 4

@luka good, but i said "Do not use string." ;)

Answer 5

Is the output an array of integer numbers?
eg.: [1,2,5,6,8]

Answer 6

@Baptiste E. Prunier nice way XD but...

Answer 7

@Megatron, more space between digits XD & i got some problems with negative numbers

Answer 8

my practice on python https://code.sololearn.com/chtPXmPc7u0F/#py

Answer 9

C :
#include <stdio.h>

int main(){
char c;

while((c=getchar()) != '\n')
printf("%c ",c);
putchar('\n');

return 0;
}

Answer 10

Edit: Sure more spaces I forgot
Negative I will look in( 45 mins later)** I have that logic for negative as well*** Some important work****

#include <iostream>
using namespace std;

int main() {
int number, original, digit, i, n;

cin>>number;
original=number;
for(i=0;number>0;number/=10,i++);
for(n=1;i>1;n*=10,i--);

while(n>=1)
{
digit=(original/n)%10;
cout<<digit<<" ";
n/=10;
}
return 0;
}

Answer 11

Use function prototyping:

Number.prototype.divider = function() {
var p=Array.from(n+'').map(Number);
return n>0?p:p.map((v,i)=>i===1?-1*v:v).splice(1);
}

alert(12568.divider());

https://code.sololearn.com/WkBrITk3Gj6g/?ref=app

Answer 12

Works with negative number also

#include <iostream>
using namespace std;

int main() {
int number, original, digit, i, n, isneg;

cin>>number;
if(number < 0)
{
isneg=-1;
number*=-1;
}

original=number;
for(i=0;number>0;number/=10,i++);
for(n=1;i>1;n*=10,i--);

while(n>=1)
{
digit=(original/n)%10;
if(isneg==-1)
{
digit*=-1;
isneg=1;
}
cout<<digit<<" ";
n/=10;
}
return 0;
}

Answer 13

Hi all, it's my try
https://code.sololearn.com/cs4PVBH73DZf/#java

Answer 14

@calvin if u want