Python n00b-please help! - if-else script

Question

hi all, I can't figure out how to specify the user input I'm asking for to be type integer so I can run the rest of the if/ else piece:

i = input("please provide a number that you like")
input=type("int")

if i <=5:
print(i)
else:
print("whoa thats greater than 5!")
print("Let me make that smaller for you:")
i= i - 3
print(i)
print("There,now that's better , take it easy fella!")

Answer 1

Try this:

i = int(input("please provide a number that you like"))

if i <= 5:
print(i)
else:
print("whoa thats greater than 5!")
print("Let me make that smaller for you:")
i= i - 3
print(i)
print("There,now that's better , take it easy fella!")

Answer 2

if you want to specify the input type as an integer, just wrap it as an int

i = int(input("Please provide a number that you like"))

Answer 3

I don't know Python's syntax, so I speak abstract
i = input
if is int(i) == false:
raise TypeError: Given value must be an instance of integer, type(i) given.

Answer 4

Then use 'try-except' block to check if any of exceptions is raised. You can lesrn more in SL course

Answer 5

Raise an exception.

Answer 6

Thank you very much for the reply. How exactly would I do that?

Answer 7

Thanks guys!