Pattern qustion

Question

1
1 2 1
1 2 3 2 1
1 2 3 4 3 2 1

Answer 1

print(' 1\n 1 2 1\n 1 2 3 2 1\n1 2 3 4 3 2 1')

Answer 2

a = 5 #Input

tab = 10 #tab in pattern

for r in range(0, a):
b = []
print ' '*tab,
for c in range(0,2*r+1):
if c <= r:
b.append(c+1)
else:
b.append(2*r+1-c)
print ''.join(map(str,b))
tab -= 1

this will give the output as
1
121
12321
1234321
123454321

Answer 3

@Kuba you can just print it as a multiline comment. It won't matter

Answer 4

For i in range(5):
print((5-i)*" ",end="")
print(list(range(1,i))+list(range(i,0,-1)),sep=" ")

Answer 5

@vengat

the pattern produced from your code produces list of elements ! Not the pattern described by the submitter

Answer 6

You need a code for it?