Add all Even and Odd Numbers from the Entered Number

Question

How to add even and odd number from entered number.

Answer 1

#include <iostream>
using namespace std;

int main() {
int i = 1, n, odd = 0, even = 0;
cin>>n;
while(i <= n){
if (i%2!=0)
odd += i;
else
even += i;
i++;
}
cout<<"Even sum:"<<even<<"\n";
cout<<"Odd sum:"<<odd;
return 0;
}

Answer 2

https://en.m.wikipedia.org/wiki/While_loop

Answer 3

it just adds 1 to the operand
e.g. i += 1 is same as i++

Answer 4

Ask if you need any help.
Welcome :)

Answer 5

Are you talking about range of numbers?

Answer 6

like if I entered 5
1, 2, 3, 4, 5
odd-sum = 9
even-sum = 6

Is this what you want?

Answer 7

I really dont know what while means even the sign ++,+=,+-, my prof focuses on smart students, he choose who to guide.

Answer 8

a += b is equivalent to a = a + b
a -= b is equivalent to a = a - b
a++ or ++a increments the value of 'a' by 1

Answer 9

What's the use of incrementing?

Answer 10

Thanks for the Help!

Answer 11

my prof told us to use "while"

Answer 12

Yes

Answer 13

Thanks!