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[Challenge: Reverse Percentage]
Okay, So you have a price of 100$ and need to add 19% tax. Piece of cake. ==> 119 The challenge: The Price of the item is 100$ including tax. How do you calculate the value that will become 100 when added 19% tax?! Your method should take 2 arguments as the parameters: one for the desired value (including tax) and one for the % and return the base price w/o tax which will then result in the desired value if you just add the tax %. It should be precise!
11 Respostas
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JavaScript:
var a = prompt("").split(" ");
alert((100 * (a[0] - 0)) / (100 + (a[1] - 0)));
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money=int(input("How much money? "))
print(money)
taxadd=int(input("What percent added? "))
print(taxadd)
plus=money/100*taxadd
print(money+plus)
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Beside the input: good idea. But not very user friendly 😜 and wrong as it returns a number which needs to be multiplied by 100 to get the basic w/of tax
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Wouldn't that be 119 instead of 84,03?
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You mean you want the code to generate a function that calculates the result of this formula: val/(100+proc)*100 ?
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Even if you buy 1,000,000 you get a difference of 0.0001, so it is irrelevant.
But if you don't round that value the end result of the total sales might be close to reality because some transactions will cancel other transactions (gain on same, lose on some).
Plus, any accountant will ask you to round up the VAT not the price just so they think they are on the safe side. :)
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Basically yes and no. Well actually just no. It would be + something, not *. But: imagine Val is 100 and proc is 10. We are searching for a number that will become 100 when you add 10%. Your code: 100/(110)=90,9090909 × 100 != 100......
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And if you add 10% of 90.9090909 to 90.9090909 you get 100. How is that not answering your original question?
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That would nearly answer it. Except it will be 99.9999999999 ;-)
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Of course. And all the prices in the stores have 10 decimal points. :)
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No, but if you buy 100 might matter. The trick is to round the first result, in this example you get 90,91 if you than add 9,09 you are back to 100