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Can someone explain arrays in java to me?

I still don't quite understand how arrays work.

16th Nov 2017, 2:26 AM
Harsh Yadav
Harsh Yadav - avatar
2 Respostas
+ 2
They store values of the same datatype. {1,2,3,4,4,5,6,7,8,9} for example. For more info link to here: https://www.sololearn.com/Course/Java/?ref=app
16th Nov 2017, 3:05 AM
👑 Prometheus 🇸🇬
👑 Prometheus 🇸🇬 - avatar
+ 1
An array is a collection of elements of the same data type (String, integers, float, etc). Example Array of 5 integers: elements [1, 2, 3, 4, 5] indexes 0 1 2 3 4 As you can see, the array are zero based - the indexes start from zero. So, the first element is at index of 0. And the last element is at index of size of the array (elements count) - 1. How it works: Assume you want to get the third element: int index = 2; // (element position - 1) int[] array = {1, 2, 3, 4, 5}; System.out.println(array[index]); // Output: 3 You can print all elements by using loops. int arraySize = array.length; // (elements count) for (int i = 0; i <= arraySize; i++) { System.out.print(array[i] + " "); } // Output: ArrayIndexOutOfBound Error The error is because the loops iterates to the arraySize (5), but the last index = (elements count - 1) = 4. So, we can fix it on this line: int arraySize = array.length - 1; Or in the loop: for (int i = 0; i < arraySize; i++) { System.out.print(array[i] + " "); } Example using for-each loop: for (int num: array) { System.out.print(num + " "); } You can modify the elements in many ways, but you can't delete them, or change their data type. array[2] = -3; // [1, 2, -3, 4, 5] // Get the max sum of the elements // It must be 9, since 4 + 5 = 9 int[] arr = {2, 5, 3, 1, 4}; int maxSum = 0; int sum = 0; for (int i = 0; i < arr.length - 1; i++) { for (int j = i + 1; j < arr.length; j++) { sum = arr[i] + arr[j]; if (sum > maxSum) { maxSum = sum; } } } System.out.println("max sum = " + maxSum);
16th Nov 2017, 3:46 AM
Boris Batinkov
Boris Batinkov - avatar