I was trying to use Try... Catch Exception. What did I miss?

Question

public class catchDivideByInfException
{
public static void main(String[] args) {
int a = 2;
int b = 0;
try {
int c = a / b;
System.out.println(c);
}
Catch (Exception e) {
System.out.println("e");
}
}
}

Answer 1

@Boris He did it on purpose so he could test out exception catching.

Answer 2

You accidentally capitalized Catch. ;)

https://code.sololearn.com/cOpViB30Zg15/#java

public class catchDivideByInfException
{
public static void main(String[] args) {
int a = 2;
int b = 0;
try {
int c = a / b;
System.out.println(c);
}
catch (Exception e) {
System.out.println("e");
}
}
}

Answer 3

You can't print the result of 2 / 0, because of the / by zero exception.

Answer 4

Oh! Thanks!

Answer 5

I wasn't trying to. I was simply trying to print some letter e if an error occured...