Would this code work?

Answer 1

No it won't.
nextInt is a function, so you call it like this
nextInt();

Answer 2

it should be nextInt()

Answer 3

https://www.sololearn.com/Codes/

^You can test code here and see if it works.

As for your code, You'll want to put () on the end of nextInt, so it'll be nextInt(). Also, I changed your variable, named variable, to scnr instead. Take some time to research common practices, naming conventions, and just the typical standards for formatting your code. Trust me, that's a habit you'd rather form right now as a good one, rather than having a bad habit you're trying to break later. Save yourself time now by learning it properly.

https://code.sololearn.com/cGj32je8aGB0/#java

import java.util.Scanner;

class MyClass {
public static void main(String[ ] args) {
Scanner scnr = new Scanner(System.in);
int age;

System.out.println("what is your age?");
age = scnr.nextInt();

if(age > 16){
System.out.println("welcome");
}
else {
System.out.println(" too young");
}
}
}

Answer 4

import java.util.Scanner;

class MyClass {
public static void main(String[ ] args) {
Scanner variable = new Scanner(System.in);
int age;
System.out.println("what is your age?");
age= variable.nextInt;

if(age>16)
{System.out.println("welcome");}
else
{System.out.println(" too young");
}
}
}

Answer 5

thank you both!