Help me solve this: Sum= 1+2+3+4+...+100

Answer 1

https://code.sololearn.com/cKneqrgzdtOX/?ref=app

Answer 2

(100 + 1) * 50

Gauss was great!

Answer 3

Why don't you try it yourself, and post the code if you have trouble? We'll be here to help. 😉

Answer 4

try this, hope it helps

i = 1
sum = 0
while i ≤ 100:
sum += i
print(sum)

Answer 5

i'll try, thanx @blackcat1111

Answer 6

1+100=101
2+99=101
and so on untill 50+51=101
so...
50*101

Answer 7

use the sum of arithmetic progression :
Sn = n*(2*a+(n-1)*d)/2
For your question
n = 100
a = 1
d = 1
Therefore :
Sn = 100*(2+99)/2
= 50*101
= 5050
Thus the sum is : 5050