Can someone explain this code to me.... class ReverseNumberDemo { public static void main(String args[]) { int num=123456789; int reversenum =0; while( num != 0 ) { reversenum = reversenum * 10; reversenum = reversenum + num%10; num = num/10; } System.out.println("Reverse of specified number is: "+reversenum); } } the thing I don't get is the reversenum part......isn't reversenum=0 so wouldn't reversenum*10=0

Answer 1

hey Arzal ur thinking is little bit innocent.
in ur code reversenum is initizalized and declare to 0 is correct.after the zero operation it will add the given number of the last digits.hence process is going to till upto num=0;
while loop false it will terminate that time
and u willget new reversevalue

Answer 2

At first the reversenum when multiplied by 10 will be zero......but after that 9 will be added to it.Now, when the loop will be started again...the reversenum will be 9*10 and this will continue until the condition is justified.

Answer 3

1)any % 10 》》lastdigit

ex: 1234 % 10 》》4

2) anynumber /10 》》remove last digit

ex: 1234 /10 》》 123

hence this is a logic , till yur while loop terminates.

Answer 4

public class ReverseString{
public static void main(String args[]){
StringBuffer S = new StringBuffer("Make it reverse");
System.out.println(a.reverse());
}
}

if you run this program you will get reversed string.
but instead of it i hav given integers too im getting reversed numbers eg i hav given 123....my output is 321 is it correct???

Answer 5

ahhh I see thanks a lot bruh

Answer 6

excellent bruh I fully understand it now.....basically the code wasn't complex but the math done inside it was

Answer 7

shouldnt it be S.reverse

Answer 8

if we use S.reverse and A.reverse it is working