[ CHALLENGE 3 ] Min-Max

Question

Given an array of integers . Check if all the numbers between minimum and maximum number in array exist's within the array .

Print 'YES' if numbers exist otherwise print 'NO'(without quotes).

Input:

Integer N denoting size of array

Next line contains N space separated integers denoting elements in array

Output:

Output your answer

Constraints:

1<= N <= 1000

1<= a[i] <= 100

SAMPLE INPUT
6 4 2 1 3 5 6

SAMPLE OUTPUT 
YES

Explanation :
min 1 max 6 all number between them are 2345 are present so YES

Answer 1

https://code.sololearn.com/c220SpDVCcEv/?ref=app

Answer 2

My one-linear Python code
https://code.sololearn.com/cMyrpfNB4wHA/?ref=app

Answer 3

My try

https://code.sololearn.com/c5bt7dZOxef7/?ref=app

Answer 4

No problem buddy
Happy coding ✌🏻

Answer 5

# Python 2.7

arr = raw_input()
arr = arr[3:] # Edited!
arr = arr.split() # Turn string into a list

# Turn elements into integers
arr = map(lambda x: int(x), arr)

maximum = max(arr)
minimum = min(arr)
for i in range(minimum+1, maximum):
if i not in arr:
print "NO"
break
elif i == maximum - 1:
print "YES"

# This covers the case when arr = [1, 2] or
# arr = [1,1,1] , because the for bucle
# doesn't print anything
if abs(maximum - minimum) <= 1:
print "YES"

#(it seems a Dcoder app problem? I swear yes xD)

Answer 6

When I input 3 4 5 6 , ur code prints "Yes", but if I input 4 5 6 7 the code print "No"

Answer 7

@sebastian
The first input is size of array

Answer 8

You're right, I forgot that
It works now :)
(I'll edit mine)

Answer 9

https://code.sololearn.com/WeRoqPdYn2sy/?ref=app

Answer 10

https://code.sololearn.com/cYLFyM58wPrT/?ref=app