Why is this False in Python? print("3" < "10")

Question

Hello I'm very new to all this. I'm going through a course and wondering why this code is false in Python.

print("3" < "10")

while this is true:

print("3" < "4")

I need help! Thank you!

-Sam

Answer 1

Anything you put inside double quotes is a string
So when you compare "3" < "10", it compares character by character and as 3 comes after 1 in ASCII, hence it is false whereas when you compare "3" < "4", it is true because 4 comes after 3.
You can check the 'ord' function in python to get ASCII numbers.

Answer 2

Great Question!
when you put the number betwwen "" it means that python is only look at the number of constituent ! Not size of the number !!!
I don't know how to explain that
for example we now that 3 is bigger than 2
so if we write
("3"<"22") or
("3"<"2222211") or ....
all of them are false because there is no number that is bigger than 3
but if we write (3 < 2221) , now it's True because now python look at the size of the numbers *_*
in example that you said ("3"<"10") is False because 1 and 0 or smaller than 3

Answer 3

nb: (i) when considering string comparison you should look up ASCII chart.
(ii) don't compare string as a whole instead character by character

question 1: print("3" < "10")
you see if you compare two string of unequal length the shorter one will be increased by a space(s).
ASCII value for 3 = 5
for 1=
49
for 0=
48
for space=
32
for 4=52
note: character will be compared similarly to a dictionary
-> 3 vs 1 [3 is bigger]
-> space vs 0 [space is smaller]

since 3 is greater than 1 comparing space and 0 is then irrelevant. so ("3" < "10") is false ☑

question 2: print("3" < "4")
character 3 [ASCII value 51] is less than character 4 [ASCII value 52].
so ("3" < "4") is True ☑

for ASCII chart visit
http://ascii.cl/index.htm?content=mobile

example: evaluate
print("ant"<"and")
print("an"<"ant")
print("Zebra">"Elephant")
print("ant">"Ant")

Answer 4

Exactly Fazel