Q&A Discussões
int result = 0;
for (int i = 0; i < 5; i++) {
if (i == 3) {
result += 10;
} else {
result += i;
}
}
1 Voto
2 Respostas
int main() {
int b = 5; int arr[b] = {11, 35, 62, 555, 989}; int sum = 0; for (int x = 0; x < 5; x++) {
sum+=arr[x]
0 Voto
4 Respostas
static int Pow(int x, int y = 2)
{
int result = 1;
for (int i = 0; i < y; i++) /* this is the for loop that I don't understand.
1 Voto
4 Respostas
What is the output of this code? int result = 0; for (int i = 0; i < 5; i++) { if (i == 3) { result += 10; } else {
1 Voto
3 Respostas
What is the output of this code? int result = 0; for (int i = 0; i < 5; i++) { if (i == 3) { result += 10; } else {
1 Voto
3 Respostas
Int x=0;
For (int i=0; i <8; i++) {
x=i*i;
} what will be the output ; and what will be the value of( i) after the for loop
-1 Voto
2 Respostas
What is the output of this code? int result = 0; for (int i = 0; i < 5; i++) { if (i == 3) { result += 10; } else {
-5 Votos
6 Respostas
Why is the output 17 ?
(this is the array modul quiz(SoloLearn))
int result = 0;
for (int i = 0; i < 5; i++){
if (i == 3) {
result += 10;
}else{
result += i;
}
}
System.out.println (result);
0 Voto
5 Respostas
is there a way I can store all the values of x in this short code without having to display them using cout?
int main() {
for (int x=0; x<5; x++){
//how do i store the all the values of x without having to display them?//
}
3 Votos
5 Respostas
public class Program {
public static void main(String[] args) {
int result = 0;
for (int i=0; i<5; i++) {
if (i==3) {
result += 10;
}
else {
result += i;
}
}
System.out.println(result);
}
}
The result is 17. But how? I want to understand. please help.
0 Voto
3 Respostas
why does this code output that there is an error because the else statement doesn't have a corresponding if statement?. How do i correct this?
#include <iostream>
using namespace std;
int main() {
int a;
for (int x =0; x<5;x++){
cin>>a;
if (a<1){
cout<<"a cannot be less than 1\n";
}
else if (a>10){
cout <<"a cannot be greater than 10\n";
}
}
else{
cout<<"code can run now"<<endl;
}
return 0;
}
3 Votos
8 Respostascan someone please explain why this code keeps telling me complication error instead of outputting the value of speed.
#include <iostream>
using namespace std;
class myClass {
public:
void setcarspeed (int a){
speed=a;
}
int getcarspeed(){
return speed;
}
private:
int speed;
};
int main() {
myClass obj;
obj.setcarspeed (40);
cout<<obj.getcarspeed ;
return 0;
}
2 Votos
3 Respostaswhat is tjis code problem!
#include <iostream>
using namespace std;
int main()
{
int b = 5;
int arr[b] = {11, 35, 62, 555, 989};
int sum = 0;
for (int x = 0; x < 5; x++) {
sum += arr[x];
}
cout << sum << endl;
return 0;
}
I cannot make an array using int variable in order to define array's element number!?
1 Voto
7 Respostas
I have 10 variables called, int1, int2, int 3 and so on. The user can write one number into the console. If the user types 7, I want to add 3 to the value of int7. how do I do this without 10 if statements? can I somehow do something like, (int + "userinput") += 3?
thank you for your help! :D
0 Voto
2 RespostasQuente hoje
Help please?
4 Votes
Ejercicio Pytho
0 Votes
Online voting system
2 Votes
What is that z for
0 Votes
Suggestions needed
4 Votes
Game development
0 Votes