Q&A Discussões
Could someone please help me with this..
Write code for an applet class that contains three labels First Number, Second Number, and Sum; three text fields for displaying the values of First Number, Second Number, and Sum, respectively; a button labeled Add. The applet allows the user to enter two integer values and displays the Sum if the Add button is clicked.
Write a html page to run and display the applet appropriately
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4 RespostasArray Help
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1 RespostaHow to assign the value?
2 Votos
1 RespostaI'm trying to calculate the decimal places of pi with Ramanujan's formula. but with this code I'm getting the same output for all values of n, which it shouldn't.
from math import sqrt, factorial as f
sum=0
n=0
k=(2*sqrt(2)/9801)
while n<=100000:
sum=sum+((f(4*n))*(1103+(26390*n)))/(((f(n))**4)*(396**(4*n)))
y=1/(k*sum)
print('%.60f' % y)
n=n+1
where am I doing wrong?
2 Votos
4 Respostashey guys, I've been trying to work out the formula 'v=I*r'. But whenever I run the program and input values for I and r, it doesn't give the right answer.
This is the code
#include <iostream>
using namespace std;
int main() {
int i,r;
int v = i*r;
cout<<"what is the value of i?\n";
cin>>i;
cout<<"what is the value of r?\n";
cin>>r;
cout<<"voltage ="<<v<<endl;
return 0;
}
p/s: I'm new to programming
1 Voto
8 RespostasWrite a program that uses a dynamic array that contains 5 items of double values. The size of the array is entered when the program is run. Aldo the 5 values must be entered. These tasks are done in the main ( ) function. Then write a function to display the 5 values. The function must have a pointer variable as a parameter. The function is called from the main ( ).
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2 RespostasMatt reaches the final round of a treasure hunt. In this, he finds that as he proceeds there are flags with the number written on them at different positions. The difference between two consecutive flags can be either a or b. If he finds the number on the first flag is 0. Given three integer, first one is number of flags present, second is a and third is b. then return all the possible values for last flag for each test case.
hunt({3 1 2}) = {2 3 4}
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