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can someone help me find some logic for this?
The method PlaceInside gets a list of squares and returns them once inside each other with the same centre and placed so the biggest square lays on the X and Y axis..
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#include <iostream>
using namespace std;
int sum(int a, int b=42) {
int result = a + b;
return (result);
}
int main() {
int x = 24;
int y = 36;
//calling the function with both parameters
int result = sum(x, y);
cout << result << endl;
//calling the function without b
result = sum(x);
cout << result << endl;
return 0;
}
why is da last function cout 66 and not 48 isn't it suppose to add 24+24?
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To bind two things of similar origin but separate identities together as one unit with ability to function independently as long and the unit is not corrupted. How to set x to get y and become z permanently and protect the unit from corrupt or deviation or denying or hiding while z securely functions actively is the purpose.
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def add(x, y):
return x + y
def do_twice(func, x, y):
return func(func(x, y), func(x, y))
a = 5
b = 10
print(do_twice(add, a, b))
Please explain step by step
Which is caller here?
Explain the 3rd and 4th line ?
why in 4th line we write add(add(x,y),add(x,y)) which is function of 1st line ?
how can we write function after return statement insted of (x+y+x+y )=30?
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java class Addquot;">"quot;
quot;;">"quot;;"awesome");"dolor""haha""hihi""hoho""huhu");"ipsum""is""sit"{}+=addadd("hehe"add("lorem"add("this"classconstructor(...words)newprint()returnthis.words 1 Voto
4 Respostas