Why does this keep giving me 28 as the output?

Question

def rep():
x=input()
y=str(x)
print (y)

def equ(e):
a=str(rep)
b=len(a)
print (b)

equ(rep)

Answer 1

You probably want this.

def rep():
x = input()
return x

def equ():
a = rep()
b = len(a)
print(b)

Why 28? You did "str(rep)" instead of "str(rep())", so it actually converted the entire rep function to a string, which happens to be 28 characters long. Funny bug!

Answer 2

Here's what your code does:
It prints the length of a string obtained by converting a function into a string. Now, if that seems right to you then great!

Maybe this is what you wanted your code to do:
Read a string typed by the user and get its length.

If that is the case, here's what your code should have been:

def rep():
x = input()
y = str(x) # This is pointless, x is already a string
return x # Same thing as returning y. Different from printing

def equ(e):
a = str(e)
b = len(a)
return b

equ(rep()) # All parentheses are important here

Now, if you want your code to be better then it should look like this:

len(input()) # This does the exact same thing

Answer 3

This is just a part of a code; I do want it to give the length of what is input, but there are several layers to it. I tried just using len (input ()) but I get an EOF error from it. I will load the entire code as I have it now.... in all its bugginess

Answer 4

I want the input to be it's own entity so that I can use it later; to get it's length, reverse it, add to it, etc....

Answer 5

def rep(e):
x=input()
y=str.x
print (y)
inp=input("Give me a name: ")
x=len(inp)
if x<10:
print ('Your name has less \n than 10 letters')
else:
print ('Your name has more \n than 10 letters')

This is the start of the code, I posted it as it's own question.