Could someone give me a Hint ????

Question

I want to write a cpp program to calculate the sequence of numbers :
S=1² +2²+3²+4²+5²+6²+.......n²

I appreciate any help from you..
even a small hint.

thanks

Answer 1

@RiGeL, following @Gordie's pointers, here's how I think it would work, I know you asked for a hint, but I guess the code will explain itself better than I could, so here it is:

#include <iostream>
#include <cmath>

int main()
{
double sum {0}, limit {0};

std::cout << "Enter the top number: ";
std::cin >> limit;
std::cout << limit << "\n\n";
if(limit < 2) return 0;

for(double i = 1;i <= limit; i++)
{
sum += std::pow(i, 2.0d);
if(i < limit - 1)
std::cout << i << char(253) << "+";
else
std::cout << i << char(253);
}
std::cout << "\n\nTotal: " << sum;

return 0;
}

Hth, cmiiw

Answer 2

print n*(n+1)*(2*n+1)/6 //n belongs to a natural no
//small approach , but for bigger degrees ... u need to use loop only for that like adnam used

Answer 3

make an int sum = 0, use for loop from int i = 1, i<=n and inside write sum += i*i (sum += is same as sum = sum +....).
This way for n=2 it will be first sum = 0 + 1*1 = 1, then sum = 1 + 2*2 = 5

Answer 4

your most welcome buddy @rigel. keep coding 😀😀😁

Answer 5

@Gordie ooh thanks bro 😁....sorry rigel for wrong code....i will be working it on soon.
its 3:00am here ..........time to sleep

Answer 6

rafal what you are saying is wrong bro . you have to set the initializer value to zero
and sum+=(i*i). will give you garbage value and not the sum and square of entered number

Answer 7

@adnan Thank you alot bro really Helped😊

Answer 8

@Gaurav Agrawal thank you alot

Answer 9

@Ipang thank you a bunch