Number of letters in strings

Question

Hi guys! I have a problem with my program. What I need to do is ask the user to enter his full name(First, Middle, Last) and store it in one string - this I managed to accomplish.
Then it has to print the number of characters in the name not counting spaces -here I have problems.
Then determine and print the three parts of the full name and the number of characters in each.
And worse part: determine and print the initials in ASCII codes (decimal) for the full name.

Here is what I have so far: https://code.sololearn.com/cBY3W0hY5ujX

I'm a complete beginner in Java, and I have to make an assignment for the chapter that we didn't pass yet because I'll be in a hospital next two weeks(heart condition, high BP) and this is my only chance to don't fail the course. Professor offers me to drop it, but I can not afford to pay for it again. Any help is much appreciated!

Answer 1

//create variable x , initialize it with 0
run a loop 3 times & take user input as a word , print the word , its length & first character (use charAt(0) ) & also add the length of word to x each time
now when loop gets over , print x as the no. of characters in name without spaces

Answer 2

I do

Answer 3

Thank you so much for your answer! Noob question: I'm trying to use scanner to prompt the user for input instead of given string that you used, but it gives me an error after first name:

Enter your full name:
John Bon Jovy
Full Name: John

First Name: John 4 chars.
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 1
at assignment4.FuName.FullName(FuName.java:29)
at assignment4.FuName.main(FuName.java:8)
P.S. I need to convert it to ASCII instead of Unicode

Answer 4

P.S. how can I convert it to ASCII not Unicode? Thank you in advance. You are really helpful!

Answer 5

I found it already. Just need to cast it to int. Thanks a lot! you are the best!)

Answer 6

I think I shouldn't use a loop because the name has to be entered in one string. That's why I have a problem. Some pseudocode would be wonderful and much appreciated.