Print character of odd position given a string using JavaScript?

Question

in JavaScript

Answer 1

explain?

Answer 2

ooh i get it! also that is c++ and not js but the code is simple!

var chars = "123456789";
for(i=0;i<chars.length;i++) {
if(parseInt(chars[i])%2!==0) {
console.log(parseInt(chars[i]));
}
}

Answer 3

using js.! not c++? plz explain

Answer 4

str = "0123456"
for(var I = 0; I < str.length; I++){
if(I%2!=0){ //check if odd using modulus
cout<<I<<" = "<<str[I]<<endl;
}
}

output:
1
3
5