What will be the output? Explain.

Question

struct Ournode{
char x,y,z;
};
main() {
struct Ournode p = {'1','0','a'+2};
struct Ournode *q = &p;
printf("%c,%c",*((char*)q+1),*((char*)q+2));
return 0;
}

Answer 1

Oh, sorry!

To start, calculate what values p has. It has '1', '0', and 'a' + 2. When you add a number to a char, you go that many values up in the ASCII chart. Two characters above 'a' is 'c'.
So p = '1', '0', and 'c'.

Next, *q is a pointer to p, and it's pointing to p's first byte (which contains '1').
When you add a number to a pointer, you make it point that many bytes further up. Since chars are 1 byte, *q + 1 will take you to its second value, '0'. *q + 2 goes to the third value, 'c'.

So knowing all this, which two characters are being output by printf()?

Answer 2

Hey, Diwakar! If you have any quiz suggestions, please submit them to the Quiz Factory.
Tap the … menu in the corner to find it. Thank you!

Answer 3

thank you

Answer 4

I know that but in the above question I need the explanation on the output. By the way thanks for your suggestion.