+ 1
Expain me please what's going on?
class Rock { int age; public static void main(String[] args) { Rock r1 = new Rock(); r1.age=19; System.out.println(r1); } }
3 ответов
+ 2
when u use obj.var its printing the value...
when u try to print the obj directly...it prints the address...
>>
when u have a pre existing class
and u hav creayed a object of that type..
supposr....
Classname obj = new Classname();
then the "obj" is not actually tge created object...
the "obj" is a pointer to the memory location of that object...
so when u print..
System.out.println(r1);
it certainly prints the address..
+ 3
You print object rather than object's value which is age. So, output will be memory location of Rock object. If you want to print '19', use println(r1.age) instead of just 'r1'.
+ 1
Here age is instance variable
So to access instance variable, you have to use object
Use "r1.age" instead of "r1" in your code
In System.out.println