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What does it mean when we equals content of a pointer variable to address of 1st element of array?
int value[20]; int * ptr; *ptr==&value[0]; what does the above code mean? don't worry about the function. it's quite different from ptr=&value[0];
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The statement *ptr==&value[0]; is an invalid statement, so it really means nothing. You can't compare an integer value (*ptr) to an address/int* in this case (&value[0]).
I created some code for you to look at in case it may help you understand.
https://code.sololearn.com/cAn4ufOuAkKX
if your intention is to point the pointer to the first element of the array, you first need to make sure you're using the assignment operator(=). The following two statements would do this:
ptr = value; //an array name is itself a pointer which is why this works
ptr = &value[0];