I can not figure this out. Write a program using an array to prompt for 10 grades and add them all up and divide by 10 to find the average. If a user inputs a negative number, add up all the numbers that are not negative and divide it by the amount of numbers that are not negative. Using two functions other than main.

Answer 1

#include <iostream.h>

int average(array[]){
int sum=0;
int j=0;
for(int i=0; i<array.size(); i++){
if (array[i]>=0){
sum+=array[i]
j++
}
}
return sum/j
}

void print(array[]){
// array.size is length of array
for(int i=0; i<=array.size(); i++){
cout<<array[i];
}
}

int main(){
int nos[10 ];
cout<<" Enter the scores ";
for( int i=0; i<=10; i++){
cin>>nos[i];
}
cout<<" average of the" <<print(nos[])<< " is"<<average[nos];
return 0;
}

Answer 2

Thomas this will reject all negative nos and give average of only positive nos

Answer 3

Thank you so much

Answer 4

I love you this solves all my problems thank you!