Need help with pointers

Question

#include <stdio.h>
int main()
{
char *s= "hello";
char *p = s;
printf("%c\t%c", p[0], s[1]);
}

when executed output was : h e
why??? in printf.. i typed p[0] not s[0]... still it prints h
need some explanation here..

Answer 1

p is of the same type as s. after the assignments p and s are both of the same value (ie the address of the first character of the string "hello")
So p[0] is the same as s[0], which is h.