Challenge:Input any number and find whether the number is even or odd without using any logical and relational operators..

Answer 1

👉take the number as String , and take out last character & use .equals("0")||.equals ("2")||.equlas ("4") ....equals ("8")
//well here I used some restricted operators
👉make use of modulo(%)
👉run a loop & substact 2 repeatedly if num >0 , now compare num+"" with "1" using .equals method ... if true then odd else even
//thinking ....

Answer 2

https://code.sololearn.com/cL4R3kVzdRb9/?ref=app

Answer 3

#include <stdio.h>

int main()

{

    int number;

    //input an integer number

    printf("Please input an integer number: ");

    scanf("%d",&number);

    //check 0th bit of number is 1 or 0

    (number & 0x01) ? printf("%d is an EVEN Number.”, number) :  printf("%d is an ODD Number.",number) ;

    printf("\n";)

    return 0;  

}

Answer 4

n=str(input())
if n[-1] in list(range(0,10,2)):
print('even')
else:
print('odd')

Answer 5

https://code.sololearn.com/c07vjWirgFUo/?ref=app Can you check it?