what does a 'return' mean exactly in javascript?

Question

please evaluate with an example.

Thanks in advanced.

Answer 1

return in short is the variable that function will value and itself behave like the value.
var a=5;. here a is 5;
var b=a;. here b is 5;
var c=sqr(a) here c is 25 as the function has code that returns a*a and it behaves like that

Answer 2

Answers to your questions:

Note: Any method declared void will not return a value. To use a 'return' statement, method must not be declared void and must contain a return statement with a corresponding return value e.g:

return returnValue;

Please look at the example below:

class Symbad {
public static void main(String[]args){
int sym = max(6,21);

System.out.println(sym);
}
static int max (int a, int b){

if (a > b)

{return a;}
else
{return b;}

}
}

Explanation:

int a = 6;
int b = 21;

If 'a' is greater than the value of 'b', then it will return 'a' and if 'a' is not greater than 21, it should return the value of 'b' that is why the else statement was used.

I hope this helps.

Answer 3

Answers to your questions:

Note: Any method declared void will not return a value. To use a 'return' statement, method must not be declared void and must contain a return statement with a corresponding return value e.g:

return returnValue;

Please look at the example below:

class Symbad {
public static void main(String[]args){
int sym = max(6,21);

System.out.println(sym);
}
static int max (int a, int b){

if (a > b)

{return a;}
else
{return b;}

}
}

// output is 21

Explanation:

int a = 6;
int b = 21;

If 'a' is greater than the value of 'b', then it will return 'a' and if 'a' is not greater than 21, it should return the value of 'b' that is why the else statement was used.

I hope this helps.