How to get the character frequency of characters in a string using python?

Question

Sample : SOORAJ
Output : {'S':1, 'O':2, 'R':1, 'A':1, 'J':1}

This should be the output required.
Using dictionaries, keys, loops, condition statement and function.
Below is the code I got but dont know why keys is not defined before the loops. Can anyone please explain this to me.

def ch_frq (str1):
dict = {}
for n in str1:
keys=dict.keys()
if n in keys:
dict[n] +=1
else:
dict[n]=1
return dict

Answer 1

The line “keys=dict.keys()” isn’t necessary.
Try the following:

def count(st):
d = dict()
for c in st:
if c in d.keys():
d[c] += 1
else:
d[c] = 1
return d

mystr = "test"
dd = count(mystr)
print(dd)

Answer 2

Pedro Demingos
Thank you sir for the answer

Answer 3

Generally the same as Pedro suggested, but shorter, and, may be a bit faster:

def func(a):
mydict = {}
for x in a:
mydict.setdefault(x,0)
mydict[x] += 1
return mydict

s = "sololearn"
print(func(s))

Answer 4

# Aqui sin funciones.

s="sololearn"
dict = {}
for x in s:
dict.setdefault(x,0)
dict[x] += 1
print(dict)