Basic data type

Question

Why it is not updated to double during comparison and double can't be compared completely. so, question is why answer of below code is 1 and not 2.

int x=10; double y=10.0;
if(x==y){cout <<"1";}else{cout<<"2";}

Answer 1

Variable x is implicitly casted to double during comparison. The value of x and y is compared, and found to be equal. Program prints 1.

Answer 2

correct. Type casting is what I was expecting.... can't we say that double generally don't get proper comparison due to precision values unlike int....

I mean to say that double x and double y should not match with comparison sign... I used to do double comparison as below:

if(abs(x-y)<=0.0001) // This should be case instead of x==y