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Im trying to write a program to add a bonus every time u input 3 consecutive fractions that equal 1.
basically the input are grades that are a fraction points available/points gotten. i want it to b that if you get all available points for three straight attempts there is a bonus of 1/5.
3 ответов
+ 1
update : you don't need "and" operator I thought you meant each fraction equals 1 .
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is there a way to write it so i dont have to write each possibility. for example if i were to continue that way it would look like:
elif second_try ==1 and third_try ==1 and fourth_try ==1:
bonus += yourbonus
this would get kind of tiresome. i was wondering if there is a way to get the input into a list and then check every three consecutive
ps
im kinda new to this so i dont know if i make any sense
thanx!
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i'm not sure I fully understand your goal .
that's not something a beginner would do .
it's not tiresome.
here is how it would be if a beginner did it :
code :
bonus = 0
counter = 0
while counter < 3:
if counter == 0 :
first_number = float(input("Enter the first fraction :"))
counter += 1 # increment counter by 1
elif counter== 1:
second_number= float(input("Enter the second fraction :"))
counter += 1
else:
third_number = float(input("Enter the third fraction :"))
counter += 1
# we collected the three fractions .
# check if they equal 1
if first_number+ second_number + third_number == 1:
bonus += bonusvalue # add a bonus
else:
print(" you didn't get the bonus")