Problems

Question

pls ans my code...
https://code.sololearn.com/c5nrYNuG3L6D/?ref=app
https://code.sololearn.com/c5nrYNuG3L6D/?ref=app

Answer 1

Simple answer: You can't access a member of a super parent's class.
If you need to do that you have to redesign your classes. The sub sub class shouldn't need to access the super super class A. B should be able to handle the request from the subclass on it's own (encapsulation principle is broken otherwise).

Answer 2

You can also do this, add this function to class b. then call it from class Program
void Display(){
System.out.println(super.m);

}
the whole class should look like this:
class A
{
int m=10;
}

class B extends A
{ int m=50;

void Display(){
System.out.println(super.m);

}
}

public class Program extends B
{
int m=100;

void display()
{
int m=200;
System.out.println(m);
System.out.println(this.m);
System.out.println(super.m);
super.Display();

}

Answer 3

Change
void Display(){
System.out.println(super.m);

}
}
to:
int Display(){
return super.m;}
and then do this:
System.out.println(super.Display());

Answer 4

Well:
int Display(){
return super.m;}
means this.
int Display = a function named Display which will return an integer value.
return super.m; means return the m value from my super class.
since were in class b so its parent is class a. which has the m value of 10.
because of that . super.m=10;
so we define this function:
int Display(){
return super.m;}
which will return the value of m in the parent of class b(class a).which is 10.

Answer 5

try this:

System.out.println(m);
System.out.println(this.m);
System.out.println(((B)this).m);
System.out.println(((A)this).m);

Answer 6

that working..
great job M N
can you explain me pls

Thanks all of you

Answer 7

Do you need explanation on the function i suggested you?

Answer 8

pls see the code everyone and reply me

Answer 9

Replace line 27 with
System.out.println(new A().m);
n you will get 10 :)

Answer 10

bro..
i got your point..
but.
i want to acces without create an object of that class

Answer 11

actually problem is..
My teacher say..
you can
only call there

class A
{
int m=10;
}

class B extends A
{
int m=50;
}

public class Program extends B
{
int m=100;

void display()
{
int m=200;
System.out.println(m);
System.out.println(this.m);
System.out.println(super.m);
System.out.println();//only here

}
public static void main(String[] args)
{
Program p=new Program ();
p.display();
}
}

Answer 12

I understand your point
Tomer Sim

Answer 13

Sorry bro it violates encapsulation.

You can use implementations like ((a)this)... but that is different from the concept of parent and super class.

It's fine to say, "No, I don't want my own behaviour - I want my parent's behaviour" because it's assumed that you'll only do so when it maintains your own state correctly.

However, you can't bypass your parent's behaviour - that would stop it from enforcing its own consistency. If the parent class wants to allow you to call the grandparent method directly, it can expose that via a separate method... but that's up to the parent class.

Sorry for late reply. Hope it helps.

Answer 14

Thanks i got it..
SatyaJit

Answer 15

i appreciate

Answer 16

that a great idea
Tomer