I cant chance variables with def

Question

I wrote a code like this and ran it:
---------------
a=10
b=10

def func():
a+=5
b-=5

func()
print(a,b)
----------------

I got an error message. I don't know why it is not working. Where did I make mistake?

Answer 1

#Finally got it.

a=10
b=10

def func():
#tell explicitly to use a and b
global a
global b
a+=5
b-=5

func()
print(a,b)

Answer 2

Maybe this could help:
https://code.sololearn.com/cueKnX0jJx99/?ref=app

Answer 3

Timon Paßlick thank you I don't use python very often so I didn't know we could write that. By the way I'm sorry I haven't noticed your previous answer.....😥😧

Answer 4

Timon Paßlick oh I don't know if it works I thaught it did since you posted it......

Answer 5

you should try this
a = 10 #actually no need to define this
b = 10 #actually no need to define this

def func(a=10,b=10):
print(str(a+5) + "," + str(b-5))

func()

Answer 6

No, It works like this. But if you use them in def, it not works.

Answer 7

Timon it worked and easy. Ty (^-^)

Answer 8

GLOBAL a = 10
Maybe, not sure.

Answer 9

I tried all of them. Not working. Can anyone fix this code and send me?

Answer 10

Try to avoid += and -=, maybe Python doesn't support it.

Answer 11

Ayastar I'm officially too dumb, sorry.

Answer 12

Ok, so, func actually has no idea that a and b exist. It doesn't know anything outside of itself. So here's how you do what you're trying to do:

a = 10
b = 10

def func(x, y):
x+=5
y-=5
return x,y

a, b = func(x,y)
print(a,b)

Answer 13

So that was correct? I found it not to work and therefore, I deleted the post mentioning you.

Answer 14

Uni You're faster than I can delete. ( ;

Answer 15

put the print statement inside the function and try running again.