+ 2

for 1=i<=10 (sum+=1/i )

I really don't get how this code works if someone could please explain it to me, step by step, that would be great. Thanks. https://code.sololearn.com/clGLW2pLnyhL/?ref=app

13th May 2018, 5:38 PM
noa
4 ответов
+ 2
The following lines for( i=1;i<=10;i++) sum+=1/i; do the following: On the first iteration of the loop, i is 1, so adds up 1 to sum. Then on the following iterations of the loop it attempt to add a fraction <1 but since i is an integer it adds 0. so in the end when printing sum, it prints 1.0. If you change i to be a float you will see sum incremented by 1/2 + 1/3 + etc...
13th May 2018, 5:53 PM
ifl
ifl - avatar
+ 1
but is it not the point of the double to store numbers with digits beyond decimal point?
13th May 2018, 5:58 PM
noa
0
yes and it does( it prints 1.0 rather than just 1) but because i is an integer you never add the decimals to sum in the loop, 1/i is always rounded down to zero for i>1.
13th May 2018, 6:00 PM
ifl
ifl - avatar
0
so, to store a doble every variable in equation has to be a double. Thank you for your answer.
13th May 2018, 6:03 PM
noa