Infinite Parameters

Question

Please guys i need to see the syntax for declaring functions with infinite parameters in this languages..
c++
c#
java
ruby
I want functions like Out(1,6,8,5) that can accept any number of arguments.All help is appreciated

Answer 1

well .... 😏😏😏
Ruby also support optional parameter...

def Out(*p)
p p
puts p.count
end
Out(1,6,8,5)

(*p) --> takes parameters as arrays...
(**p) --> takes as hash...😎😎😎
func(a:1, b:2)
Ruby Rocks...✌️😏😏😏
_____________________________________

In C++ u can pass an array as parameter..
lol 🤣🤣🤣
#include <iostream>
void Out(int *a, int size);
int main() {
int a[] = {1,6,8,5};
Out(a, sizeof(a)/sizeof(*a));
}

void Out(int *a, int size) {
for (int i = 0; i < size; i++)
std::cout <<a[i]<<" ";
}
_____________________________________

C# also support optional parameter but I don't know if it can take 1 or more at a time....
U can do this 👇
static void Main(string[] args)
{
Out(1,6,8,5);
}
public static void Out(params int[] list)
{
for (int i = 0; i < list.Length; i++)
{
Console.Write(list[i] + " ");
}
}
____________________________________

for Java as Dev suggested...

Answer 2

Jan Markus one day the other languages will attack you for trying to brainwash everybody into python!😂
You keep telling everybody to do python

Answer 3

You might look to use Varargs in Java, but that's just an hidden array implementation.

Take a look at this example code:

private static void varargs (int ... args) {
for (int i: args)
System.out.print(i + " ");
}

This can have any number of arguments passed to it!

varargs (3, 9, 4, 80);

https://docs.oracle.com/javase/1.5.0/docs/guide/language/varargs.html

Answer 4

Jan Markus i already knew how to that with py😂.the languages i listed dont seem to have an obvious way of doing it