Why i can't see the number without duplication.

Question

Why i can't see the number without duplication.

import random
def rand():
    list=[]
    while len(list)<6:
        i=0
        a=random.randrange(1,10)
        for i in range(len(list)):
            if a==list[i]:
                pass
        list.append(a)
    b=random.randrange(1,10)
    return list, b 

how i can see the another number without set, remove, in function?
i want to check duplication number at [for] and after [while] i want to add number to list.
what is the mistake?

Answer 1

It sounds like you want a list with completely different numbers. This can be easily checked with:

if a not in list:
list.append(a)

Use this instead of pass! I’ve included a code you may use.

https://code.sololearn.com/c55423VpwNRo/?ref=app

Answer 2

Look now, I think the problem was in your [for] loop. When the code first starts, your list doesn’t have any numbers. So when it first tries to loop over the length of the list, it stops because the range == 0. Add a random number to the list first, and then run your for loop!(:
https://code.sololearn.com/c55423VpwNRo/?ref=app

Answer 3

I actually saw a bug, give me a second

Answer 4

Works now!

Answer 5

wow! i will try this after 30minutes!!
thank you for your teaching :) :D

Answer 6

When I saw your code you had the b variable too, is that what you’re seeing as the duplicate? None of the numbers in the list are duplicated. I just took out the b variable. Check again(:

Answer 7

oh I'm sorry. it works properly!!
wow thank you so much!!
you are genius :D

Answer 8

thank you so much :)
but it is [in] function. ㅠㅠ
my teaching assistant will not want to use that.

Answer 9

ok! thanks! i will try again :)

Answer 10

ㅠㅠㅠ it is also has duplication number