Lambda issue

Question

Please help in describing below code:

a = (lambda x: x**3)((lambda x: x+2)(1))

print(a)

Output is : 27

Answer 1

The above code can also be written like so:

b = (lambda x: x+2)(1)
a = (lambda x: x**3)(b)

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Think of the first line like this:

def func(x):
return x + 2

b = func(1)

Here, we are passing an argument of 1 to 'func', which returns the value of 1 +2, which means b is now equal to 3.

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In the same way, the second line can also be written like this:

def func2(x):
return x**3

a = func2(b)

Just like the first line, we are passing the value of b to func2, which returns b**3, that is 3**3 which finally results in 27.

Let me know if I can clear anything up :)

Answer 2

that's not an issue,
lambda x: x**3 took ((lambda x: x+2)(1)) as it's argument, these 3 steps should explain:

a = (lambda x: x**3)((lambda x: x+2)(1))
a = (lamda x: x**3)(3)
a = 27

Answer 3

honestly a lot of the problem is we are missing the original programmers notes in code on the screen. if the programmer codes correctly notating their work a large amount of confusion would be taken out... seems like WET work.

Answer 4

Thank you Just A Rather Ridiculously Long Username and Seb TheS