In my this code it show that it is too large number I use long rather it show error! So why it show error???

Question

https://code.sololearn.com/cZz4VJUaYOPa/?ref=app

Answer 1

@Harsh Agrawal

When you're using a long literal (such as in your object's input method), you need to put an L at the end to designate that it's a long literal.

CHANGE:
ob.input(5689,7000695791,15,"harsh");

TO:
ob.input(5689,7000695791L,15,"harsh");

^As you can see, I put an L at the end of 7000695791 to correct the issue.

::::OUTPUT:::::
bike no phone no name no of days charge
5689 7000695791 harsh 15 10500

Answer 2

okkkk thnxxxx Fata1 Err0r