Someone please help me with this code. How did the output work?

Question

int i [] = {1,2,3,4,5,6,7};
int j = 4;
cout<<i[++j];
// my answer is 5.But output says 6.

Answer 1

That's because you did Pre-increment j, before passing it to the array.

It works like this::
int i[]={1,2,3,4,5,6,7}
int j=4;
cout<< i[++j];

The reason you got 6,is because you first of all added 1 to j >>[++j]<<
This makes j= 5, not 4.
Then the compiler now sees the command as ::
cout<<i[5];
And i[5] =6;

Answer 2

its 6 cause ++j will be 5 not 4 so 5 index is 6 in the array

j++ = 4
++j = 5

Answer 3

well idk c# but in c++ is like that, if you use ++j it will increment the variable and then use it, if you use j++ it will use the variablen and then increment it (maybe you are just confused as far as i know is the same in c# and c++)

Answer 4

step:1 int i[] = {1,2,3,4,5,6,7};
step:2 that means i[0]=1, i[1]=2, i[3]=4, i[4]=5, i[5]=6, i[6]=7;
step:3 now int j=4;
step:4 then
step:5 cout<<i[++j];
step:6 in the step:5 ++j means j=1+j
step:7 so from the step:3 j=4
step:8 apply step 7 (i.e j value) in step 6
step:9 so we get the value of ++j means j=1+4
atlast we get the j value as 5
step:10 so insert the j value in step:5
step:11 cout<<i[++j]; changed as cout<<i[5]
step:12 i[5]=6 this is from step:2
step:13 so the output says 6

Answer 5

but its pre ++ not post so it should be 4. actually i know pre and posr from C#. is there any difference?

Answer 6

Lol 😂 This differnce of c# and C++ costed me my challenge win. Thanks for replying so soon . you guys help a lot