[SOLVED] Fahrenheit to Celsius Table in JAVA

Question

Given three values - Start Fahrenheit Value (S), End Fahrenheit value (E) and Step Size (W), you need to convert all Fahrenheit values from Start to End at the gap of W, into their corresponding Celsius values and print the table.

INPUT FORMAT
3 integers - S, E and W respectively separated by space.

OUTPUT FORMAT
Fahrenheit to Celsius conversion table. One line for every Fahrenheit and corresponding Celsius value. On Fahrenheit value and its corresponding Celsius value should be separated by tab ("\t")

Sample
IN====> 0 100 20 //(S E W)
OUT====>
0 -17
20 -6
40 4
60 15
80 26
100 37

Answer 1

don't worry i figured it out
https://code.sololearn.com/cj1J3YdP4Hz3

Answer 2

Here's the code for this question

#include<iostream>
using namespace std;

int main()
{
int s,e,w,i,cd;
cin>>s;
cin>>e;
cin>>w;

for(i=s;i<=e;i+=w)
{
cd=(i-32)/1.8;
cout<<i<<"\t"<<cd<<"\n";
}

}

Answer 3

Where is your code?

Answer 4

code??

Answer 5

start = int(input())
end = int(input())
step = int(input())

curr_temp = start

while curr_temp <= end:
c = 5/9 * (curr_temp-32)
print(curr_temp, " ", int(c))
curr_temp = curr_temp+step

Answer 6

def printTable(s, e, w):
# Implement Your Code Here
while True:
c = 0
if s <= e:
c = (s - 32) * 5 / 9
print(s, int(c))
s = s + w

else:
break

s = int(input())
e = int(input())
step = int(input())
printTable(s, e, step)

Answer 7

S = int(input())
E = int(input())
W = int(input())
count = S
While count <= E :
A = (S-32) *5/9
print(S, "/t", int(A))
Count = count+W