Dice Game

Question

# NOW trying to write a code such that diceA is never equal to (!=) diceB i wrote this
import random
diceA = random.randint(1,6)
diceB= random.randint(1,6)
while True:
if diceA != diceB :
Roll_a=str(diceA+diceB)
print ("Result:"+Roll_a)
break
else:
diceB2 = random.randint(1,6)
Roll_b=str(diceA+diceB2)
print("Result:"+ Roll_b)
break
#output still returned 12 after sometime.

Answer 1

#Try this
from random import choice as c
dice_out=list(range(1,7))
diceA = c(dice_out)
diceB= c([i for i in dice_out if i!= diceA])

print(diceA+diceB)

Answer 2

Thanks.
This works too.
having a hard time understanding this though.
and the print fxn is not within the while variable.

Answer 3

I'm a newbie. I saw that too. but then I pressed f5 so many times before that logic failed.
how do I limit diceB

Answer 4

Thanks so much.

Answer 5

In general, this means

try
while "not OK"
try again

some other languages allow post loop verification, so it looks like

do
try
while "not OK"

this is easier to read.

Answer 6

There is an error in your logic.

In the case where else: is called, nothing limmits diceB2 from ending up the same as diceA.

Answer 7

#output still returned 12 after sometime.
this happens when all diceA, diceB and diceB2 equal 6.

try the following:

import random
diceA = random.randint(1,6)
diceB = random.randint(1,6)
while diceB == diceA :
diceB = random.randint(1,6)
print("Result:", diceA + diceB)

Answer 8

Money outside play with man