Is there a way to know maximum 'value'(not size) that a data type can hold??like long long int?

Answer 1

It depend from the bit used to data type... if I remember correclty "long long" use 64bit... so 2^64 = 18446744073709551616 (very little ah? ahaha). But this long number is divided by 2, because exist positive and negative numbers ;) so +9223372036854775808 and -9223372036854775808!!! :)

Answer 2

to be very precise +9,223,372,036,854,775,807 and -9,223,372,036,854,775,808... but they are details :) (the positive number include the 0, so the tot-1!!)

Answer 3

try it and let me know if that's what you're looking for ->
https://code.sololearn.com/cQi5v6w9rBov/#cpp

other key of limits.h library are:

CHAR_BIT = number of bits in a char
SCHAR_MIN = minimum value for a signed char
SCHAR_MAX = maximum value for a signed char
UCHAR_MAX = maximum value for an unsigned char
CHAR_MIN = minimum value for a char
CHAR_MAX = maximum value for a char
MB_LEN_MAX = maximum multibyte length of a character accross locales
SHRT_MIN = minimum value for a short
SHRT_MAX = maximum value for a short
USHRT_MAX = maximum value for an unsigned short
INT_MIN = minimum value for an int
INT_MAX = maximum value for an int
UINT_MAX = maximum value for an unsigned int
LONG_MIN = minimum value for a long
LONG_MAX = maximum value for a long
ULONG_MAX = maximum value for an unsigned long
LLONG_MIN = minimum value for a long long
LLONG_MAX = maximum value for a long long
ULLONG_MAX = maximum value for an unsigned long long

Answer 4

THANKS MAN!!!!!It works.... for ULLONG_MAX and LLONG_MAX anyway.😀I think the rest will work too.Thanks again!

Answer 5

it's true,but I need to display the message "number out of bounds" if the number obtained after an operation say ' * ' can't be stored in a variable.Also it would be difficult to check it against such a large number (provided I "magically" remembered it!😅)
hence a keyword that has it stored already would be really helpful!!!