A c++ that converts char into ASCII number and vice versal.

Question

i tried using int(word[1]) to convert character array into a number.

Answer 1

Show your attempt, You need to prove that you tried to make the code.

Answer 2

i need a function that convert ascii number into symbols

Answer 3

Thats not c++ casting sintax. In c++ you cast like (int)word[1]

Answer 4

In c++ you don't need a function for this. You don't even need to cast. E.g. if you have:

int a = 'a';

the a variable will be 97 (ascii code for 'a').

and if you have:

char b = 97;

b will be 'a'

You can even do some math with char.

E.g. 'a'+1 will give you 98. Or 'b' if you cast like (char)('a'+1)

Just check that out

https://code.sololearn.com/cgPoe26gc2Pt/?ref=app

Answer 5

there is a default value for each char. why u need to convert?

Answer 6

this is a code in java it gives u an idea*******************

import java.util.Scanner;
/**
* Title: ASCII character codes viewer
* Author: Igor Makarsky
* Instruction: Enter a string and you will get codes of each char.
*/
public class Program
{
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
String word = sc.nextLine();
char[] chars = word.toCharArray();

System.out.println("You entered: " + word);
System.out.println("Here are ASCII character codes.");

for(char c : chars) {
System.out.printf("%c: %d\n", c, (int) c);
}

printTitle();
}

private static void printTitle() {
String title = "ASCII character codes viewer";
String border = "";

for(int i = 0; i < title.length(); i++) {
border += (char) 205;
}

System.out.println((char) 201 + border + (char) 187);
System.out.println((char) 186 + title + (char) 186);
System.out.println((char) 200 + border + (char) 188);
}
}