can any body explain me sum += myArr[x]; this part work.

Question

int [ ] myArr = {6, 42, 3, 7};
int sum=0;
for(int x=0; x<myArr.length; x++) {
sum += myArr[x];
}
System.out.println(sum);

// 58

Answer 1

You have a lot of friends btw.

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Answer 2

QailBee 🤴🏼

Well what coincidence for it no longer surprises me or the tiny fragment of whatever is left of me.

Answer 3

sum is originally 0.

You create a loop which loops from x = 0 to x = myArr.length.

Within this loop, myArr[x] would be each array element within myArr.

For each execution of the loop, the value of the array element is added to sum.

6 + 42 + 3 + 7

58

Answer 4

myArr is an array. You can access the single elements of the array with the square brackets. The for loop will start with x = 0.

In the for loop, the sum will be += myArr[x] which is same as: sum = sum + myArr[x] which means something is being added.

Each iteration x will be increased once till it is te length of the array (4). So with this you sum up each elemenet of the array ( from 0 to 3, with 0 being the first).

Answer 5

It surprises me people do not search their question beforehand Hatsy Rei haha