+ 1

a=[1,2,3,4,1] for n in a: a[n]=0 print(a)

didn't get it's output.... please explain me the right answer with logic

5th Aug 2018, 6:09 AM
Mohd Naved Ansari
6 ответов
+ 3
Oh so it loops through the current values of a not the starting values of a loop 1 sets the value of a[1] to 0 loop 2 sets value of a[0] to 0 loop 3 sets value of a[3] to 0 at this point we are at a = [0,0,3,0,1]
5th Aug 2018, 6:40 AM
JME
0
What were you expecting? n in a will go through the values in a in order. if you are trying to set every value in the array to 0 then do for n in range(len(a)): a[n] = 0
5th Aug 2018, 6:19 AM
JME
0
Jason Edelson i was expecting the output [1,0,0,0,0] but the correct output is [0,0,3,0,1]
5th Aug 2018, 6:30 AM
Mohd Naved Ansari
0
#This code explains itself a=[1,2,3,4,1] print(set(range(len(a)))) for n in a: print(f'{a} a[{n}]={a[n]} -> 0') a[n]=0
5th Aug 2018, 6:39 AM
Louis
Louis - avatar
0
Jason Edelson Thanks buddy
5th Aug 2018, 6:44 AM
Mohd Naved Ansari
0
a=[1,2,3,4,1] for n in a: print(n, end=": ") a[n]=0 print(a) If you print the n, you will know what happens. It uses the next element of the updated array. Interesting to know, I did not know that before 😅 For expected output use: a=[1,2,3,4,1] b=a.copy() for n in a: print(n, end=": ") b[n]=0 print(b)
5th Aug 2018, 6:49 AM
Matthias
Matthias - avatar