May you explain the code please? why it is giving 20 as output?

Question

#include<bits/stdc++.h>
using namespace std;
void func(int&x)
{
x=20;
}
int main()
{
int x=30;
func(x);
cout<<x;
}

Answer 1

thank you.

Answer 2

Because you pass by reference.
Meaning that you manipulate the variable x at the same memory address and don't create another local x in the function.