{ int a = 100; a = 50; cout << a; return 0; } Why the output is 50 as the value of a is 100 & 50

Answer 1

The work is with these lines
int a = 100;
a =50
You first thing tell C++ to give "a" the value 100
The second line tells C++ to replace the former value of "a"(100) , with a new value (50)

Answer 2

the second value replace the first value...
so 100 be 50

Answer 3

but what did you expect to change the initial value of 100 to 50? Variables can not store multiple values ​​if they are neither structures, nor classes, nor unions

Answer 4

they are right

Answer 5

ahhh c++ :-)

Answer 6

As after intializing the value of a to 100 its value is changed to 50

Answer 7

the program changed the output to 50 becsause u told it to :)
u changed the value from 100 to 50