Do I read this code wrong?

Question

#####Python
#### What’s the result of this code?
triple = lambda x: x * 3
add = lambda x, y: x + y
print(add(triple(3, 4))

######In this line of code I entered the value’s of x in the first two lines. So I get 3*3=9 for the first x and for the second x I was pondering for awhile. To calculate that I need the value of y and I couldn’t find any value for that in the code so I assumed that it would return as a 0. Therefore for the second x I came up with 4+0=4.
But what I don’t get is why the code continues as 9+4..
Because I would have read 9*4..
https://code.sololearn.com/W8PUh7zJ1kQZ/?ref=app
#####

Answer 1

What is the result of this code?
triple = lambda x: x * 3
add = lambda x, y: x + y
print(add(triple(3), 4))

The Correct answer is 13.

Answer 2

Wilson Chong I think we have a problem with that code, now I understand your confusion, the 'triple' expected one argument passed, but two was passed instead => 'triple(3,4)'. I guess the correct form of the code should be along these lines:

triple = lambda x: x * 3
add = lambda x, y: x + y
print(add(triple(3), 4))

Here, as you see, 'triple' is called with 1 argument (3), and the 'add' is called with 2 arguments, first argument is return value of 'triple(3)' which is 9, and second argument is 4. This outputs 13 (9+4).

Hth, cmiiw

Answer 3

Thanks, now I get the code!

Answer 4

What is the result of this code?
triple = lambda x: x * 3
add = lambda x, y: x + y
print(add(triple(3), 4))

Ans: 'triple' is called with 1 argument (3), and the 'add' is called with 2 arguments, first argument is return value of 'triple(3)' which is 9, and second argument is 4.
This outputs 13 (9+4).

Answer 5

question : What is the result of this code?
program : triple = lambda x: x * 3
add = lambda x, y: x + y
print(add(triple(3), 4))
output : 13

Answer 6

correct answer is 13