a=int("5") b=list(range(1,10,2)) if a==b: print ("yes") else: print ("no")

Question

I have wish to find out whether the given number is odd or even, what is wrong in my code?

Answer 1

You are comparing an integer (a) with a list (b), this means the code will always output "no" because they are two different things. If you want to check whether a given number is even/odd you can use modulo or bitwise AND operator.

# Check number be odd/even
# using modulo operator
num = 5
if num % 2 == 0:
print("{} is even".format(num))
else:
print("{} is odd".format(num))

# Check number be odd/even
# using bitwise AND operator
num = 7
if num & 1:
print("{} is odd".format(num))
else:
print("{} is even".format(num))

Answer 2

a=5
b=list(range(1,10,2))
for i in b:
if a==i:
print ("yes")
break
else: print ("no")