Could you please explain the output of two Java statements? Topic: operators

Question

int a = 2; int b = 3;
1) --b == --a // output true
2) a == b ++ && b == 3 // output true

Could you please also tell me whether there is such a rule in Java, which demands executing the operators coming with variables before those coming with numbers? Something like here: a + b/2 == 2 // output true

Answer 1

i got false for both of these ? how are you getting true?

Answer 2

ZdzichPych

/*i ran this in code playground and both returned false*/

int a = 2; int b = 3;

boolean z = --b == --a;
boolean y = a == b ++ && b == 3;

System.out.print(z+" "+y);

Answer 3

Well, it looks this way: the first statement is presumably true on both Eclipse and SoloLearn's Playground, whereas the second one is true only on Eclipse. Meanwhile, I also feel the output should be false for both cases :/

Answer 4

Thank's for sharing your code, I write it without booleans, just: int a = 2; int b = 3; System.out.println(--b == --a);
System.out.println(a == b++ && b == 3);

Answer 5

Hi! I tried to run what you did on code playground:

public class Program
{
public static void main(String[] args) {
int a = 2; int b = 3;
System.out.println(--b == --a);
System.out.println(a == b++ && b == 3);
}
}

And the output was
false
false